A=bq+r, where o ≤ r < b
48=18x2+12
18=12x1+6
12=6x2+0 ∴ HCF (18,48) = 6 now 6= 18-12x1
6= 18-(48-18x2)
6= 18-48x1+18x2
6= 18x3-48x1 6= 18x3+48x(-1)
i.e. 6= 18x +48y
∴
6= 18×3 +48×(-1)
=18×3 +48×(-1) + 18×48-18×48
=18(3+48)+48(-1-18)
=18×51+48×(-19)
6=18x+48y
∴
Hence, x and y are not unique.
48=18x2+12
18=12x1+6
12=6x2+0 ∴ HCF (18,48) = 6 now 6= 18-12x1
6= 18-(48-18x2)
6= 18-48x1+18x2
6= 18x3-48x1 6= 18x3+48x(-1)
i.e. 6= 18x +48y
∴
6= 18×3 +48×(-1)
=18×3 +48×(-1) + 18×48-18×48
=18(3+48)+48(-1-18)
=18×51+48×(-19)
6=18x+48y
∴
Hence, x and y are not unique.
u cheat u have copied it from brainly.com
ReplyDeleteit is the exact same answer
even the position of the words are the same
in going to report u to the head of the website
Yeh vi to ho sakta han ki tuna cheat kar liya ho ga
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ReplyDelete😊
ReplyDeleteCheater
ReplyDeleteSuch a it loser you are
Whatever what harm does it do if that person has cheated at last we are in one way trying to cheat from Google.
ReplyDelete